A thin equiconvex lens of glass ( μ = 1.5) of focal length 0.3 m in air is sealed into an opening at one end of a tube filled with water 
. A concave mirror of radius of curvature 20 cm is cut into two halves M 1 and M 2 and is placed at the end of the tube as shown in figure. The principal axes of the mirrors are separated by 1 mm each from the principal axis of the lens. The gap left between the two mirrors is covered by an opaque substance. A monochromatic point source
S emitting light of wavelength λ = 5000 Å is placed 0.9 m to the left of the lens. The light reflected from M 1 and M 2 form interference pattern on the left end AB of the tube.
(i) Distance of the image formed by lens water
combination from lens is –
Text Solution
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Ans.
(i)
Sol. For lens 
= ( μ – 1) 
= 
⇒ R = 0.3 m
= 
+ 
– 
= 
+ 
⇒ v = 1.2 m
(ii)
Sol.
For mirror 0 = 1 f = – 10 cm u = 0.2 m
⇒ v = – 20 cm
= m = 
= 
= – 1 inverted
Distance I 1 I 2 = 4 mm.
(iii)
Sol. 
= 
= 1.25 × 10 –4 m
= 0.1125 mm
= 112.5 μ m
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